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(1/2)^x(4)^x-2=(8)^x+1
We move all terms to the left:
(1/2)^x(4)^x-2-((8)^x+1)=0
Domain of the equation: 2)^x4^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/2)^x4^x-(8^x+1)-2=0
We get rid of parentheses
(+1/2)^x4^x-8^x-1-2=0
We multiply all the terms by the denominator
(+1-8^x*2)^x4^x-1*2)^x4^x-2*2)^x4^x=0
Wy multiply elements
-4x^2+(+1-8^x*2)^x4^x=0
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